A smooth square plateform ABCD is moving towards right with a uniform speed v. At what angle `theta` must a particle be projected from A with speed u so that it strikes the point B

Options

A. `sin^(-1)((u)/(v))`
B. `cos^(-1)((v)/(u))`
C. `cos^(-1)((u)/(v))`
D. `sin^(-1)((v)/(u))`

Answer

b

Explanation

At `t=(1)/(8)xx(2pi)/(omega)=(pi)/(4omega)`
x-coordinate of P`=omegaR((pi)/(4))gtR cos 45^(@)`

Therefore, both particle P and Q land in unshaded region.