Three balls A,B and C are projected from ground with same speed at same angle with the horizontal. The balls A,B and C collie with the wall during a flight in air and all three collide perpendicu lary and eleastically with the wall as shown in Fig. 5.119 it the time taken by the ball A to fall back on ground is 4 seconds and that by ball B is 2 seconds. Then the time taken by the ball C to reach the ground after projection will be:

Answer

6

Explanation

`T=(2u sin theta)/(g)=4s`.....(i)
Since in second case going up time is 1s and coming back time 1s. So in third case particle will take 3s to hit the plane and 3s to come back so total time in case 3 is 6s.