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A particle is projected horizontally wit...

A particle is projected horizontally with a speed V=5m/s from the top of a plane inclined at an angle `theta=37^(@)` to the horizontal `(g=10m//s^(2))`

Find the time taken by the particle to hit the plane.

A

`(3)/(4)s`

B

`3s`

C

`4s`

D

`(4)/(3)s`

Text Solution

Verified by Experts

The correct Answer is:
a
`R=(u cos theta)T+(1)/(2)g sin thetaT^(2)`
`T=(2u sin theta)/(g cos theta)`
`V_(x)= u cos theta+g sin thetaT`
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