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A particle is projected horizontally wit...

A particle is projected horizontally with a speed V=5m/s from the top of a plane inclined at an angle `theta=37^(@)` to the horizontal `(g=10m//s^(2))`

What is the velocity of the particle just before it hits the plane?

A

`5sqrt(3)m//s`

B

`(5)/(2)sqrt(13)m//s`

C

`10sqrt(13)m//s`

D

`5sqrt(26)m//s`

Text Solution

Verified by Experts

The correct Answer is:
b
`R=(u cos theta)T+(1)/(2)g sin thetaT^(2)`
`T=(2u sin theta)/(g cos theta)`
`V_(x)= u cos theta+g sin thetaT`
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