A particle A is projected with an initial velocity of `60 m//s` at an angle `30^@` to the horizontal. At the same time a second particle B is projected in opposite direction with initial speed of `50 m//s` from a point at a distance of 100 m from A. If the particles collide in air, find (a)the angle of projection `alpha` of particle B, (b) time when the collision takes place and (c) the distance of P from A, where collision occurs. `(g= 10 m//s^2)`

Options

A. 100m
B. 50m
C. 30m
D. 63m

Answer

d

Explanation

Along x-aix 60 `cos 30^(@)xxT+(50cos alpha)T=100`
Along y-axis `60sin 30^(@)xxT-(1)/(2)g t^(2)=50 sin alphaT-(1)/(2)g t^(2)`