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Two blocks of masses m(1)=5 kg and m(2)=...

Two blocks of masses `m_(1)=5` kg and `m_(2)=2` kg are connected by threads which pass over the pulleys as shown in the figure. The threads are massless and the pulleys are massless and smooth. The blocks can move only along the vertical direction `T_(1) and T_(2)` are the tensions in the string as shown. Now match the following: `(Take g=10 m//s^(2))`

`{:(,"Column -I",,"Column -II"),("(a)",underset("acceleration of " m_(1) " with respect to ground")"Magnitude value of",,(p)500/19 "SI units"),("(b)",underset("acceleration of" m_(2) "with respect to ground")"Magnitude value of",,(q)250/19 "SI units"),("(c)","The value of tension" T_(1) ,,(r) 60/19 "SI units"),("(d)","The value of tension" T_(2),,(s) 40/19 "SI units"),(,,,"(t)None of the above"):}`

Text Solution

Verified by Experts

The correct Answer is:
`ararrs; brarr r; crarrq; d rarrp`

`T_(2)=2T_(1)`
Now, `m_(1)g-T_(1)-T_(2)=m_(1)a_(1)`
`2T_(1)-m_(2)g=m_(2)a_(2)` ...(ii)
as `y=((3x)/2)`
`2a_(2)=3a_(1)`….(iii)
By solving we will get the answer `a_(1)=(40/19)m//sec^(2)`
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