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In fig shown, both blocks are released f...

In fig shown, both blocks are released from rest Length of 4 kg block is 2m and of 1kg is 4m. Find the time they take to cross each other? Assume pulley to be light and string to be light and inelastic.

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The correct Answer is:
1
From F.B.D. of blocks A and B solve acceleration of each block
`4g-T=4a` ….(i)
`T-lg=1xxa` ….(ii)

After solving Eqns (i) and (ii) `a=(3g)/5`
acceleration of A w.r.t. B `a_(A//B)=(6g)/5=12m//s^(2)`
If A will cross B, then distance travelled by A w.r.t. B is 6m
`6=0+1/2xx12xxt^(2),t=1 sec`
For `F_(0)=4m_(2)g`
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