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Two blocks A and B having masses m(1)=1 ...

Two blocks A and B having masses `m_(1)=1 kg m_(2)=4 kg` are arranged as shown in the figure The pulleys P and Q are light and frictionless. All the blocks are resting on a horizontal floor and the pulleys are held such that strings remains just taut. At moment t=0 a force F=30 t (N) starts acting on the pulley P along vertically upward direction as shown in the figure The time when the blocks A and B loose contact with ground is `4//x` sec then x is:

Text Solution

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The correct Answer is:
2

Concept: When blocks loose contact with ground normal reaction on then becomes zero.

(i) When A looses contact
`T=10N , F=30t or 30t =30, t =1sec`
When B looses contact
`2T=40or T=20 , F=3T`
or `30t=60 or t=2 sec`
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