Two smooth block are placed at a smooth corner as shown in fig. Both the bloks are having mass m. We apply a force F on the block m. Block A presses block B in the normal direction, due to which pressing force on vertical wall will increase, and pressing force on the horizontal wall decreases, as we increases `F(theta = 37^(@)` with horizontal).

As soon as the pressing force on the horizontal wall by block B become zero, it will lose contact with ground. If the value of F further increases, block B will accelerate in the upward direction and simulaneously block A will towards right.
If both the blocks are stationary, the force exerted by ground of block A is

Options

A. `mg+(3F)/4`
B. `mg-(3F)/4`
C. `mg+(4F)/3`
D. `mg-(4F)/3`

Answer

C

Explanation

`F=N sin theta`
`N_(1)=mg+Ncos theta`