What is the concentration of sugar `(C_(12)H_(22)O_(11))` in `mol L^(-1)` if its `20 g` are dissolved in enough water to make a final volume up to `2L`?

Explanation

molarity (M) of a solution is given by ,
`=("Number of moles of solute")/("Volume of solution in Litres") `
`=("Mass of suger / molar mass of sugar")/(2L)`
`=(20g//[(12xx12)+(1xx22)+(11xx16)]g)/(2L)`
`=(20 g//342g)/(2L)`
`=(0.0585 mol)/(2L)`
=0.2925 mol `L^(-1)`
`therefore ` Molar concentration of sugar `=0.02925 mol L^(-1)`