Yellowish-green gas chlorine `(Cl_(2))` can be prepared in the laboratory by heating hydrochloric acid `(HCl, aq)` with pyrolusite (manganese dioxide, `MnO_(2)`):
`4HCl(aq.) + MnO_(2)(s) rarr Cl_(2)(g) + 2H_(2)O(l) + MnCl_(2)(aq.)`.
How many grams of `HCl` reacts with `5.00g` of manganese dioxide?

Answer

`8.40 g HCl`

Explanation

1 mol `[55+2xx16=87 g] MnO_(2)` reacts completely with 4 mol `[4xx36.5 =146 g ]` of HCl.
`therefore ` 5.0 of `MnO_(2)` will react with
`=(146 g)/(87 g)xx5.0 g` of HCl
=8.4 g og HCl
Hence , 8.4 g of HCl will react completely with 5.0 g of manganese dioide.