A ballon is filled with hydrogen at room temperature. It will burst if pressure exceeds `0.2 "bar"`. If at `I` bar pressure, the gas occupies `2.27 L` volume, up to what volume can the balloon be expanded?

Explanation

According to Boyle's Law `p_(1)V_(1)=p_(2)V_(2)`
If `p_(1)` is 1 bar, `V_(1)` will be 2.27 L
If `p_(2)=0.2` bar, then `V_(2)=(p_(1)V_(1))/(p_(2))`
`rArrV_(2)(1"bar"xx2.27L)/(0.2"bar")=11.35 L`
Since balloon bursts at 0.2 bar pressure, the volume of balloon should be less than 11.35 L.