A vessel of 120 mL capacity contains a certain amount of gas at 1.2 bar pressure and `35^(@)C`. The gas is transferred to another vessel of volume 180 mL at `35^(@)C`. What would be its pressure?

Answer

0.8 bar

Explanation

Given,
Initial pressure, `p_(1)` =1.2 bar
Initial volume, `V_(1)` 120 mL
Final vomume, `V_(2)` = 180 mL
Since the temperature remains constant, the final pressure `(p_(2))` can be calculated using Boyle's law.
According to Boyle's law,
`p_(1)V_(1)=p_(2)V_(2)`
`p_(2)=(p_(1)V_(1))/(V_(2))`
`=(1.2xx120)/(180)` bar
=.8 bar