Density of a gas is found to be `5.46//dm^(3)` at `27^(@)C` at 2 bar pressure What will be its density at `STP` ? .

Answer

`3g//dm^(3)`

Explanation

Given, `d_(1)=5.46 g//dm^(3)`
`p_(1)=2` bar
`T_(1)=27^(@)C` =(24+273) K=300K
`p_(2)`=1 bar
`T_(2)` =273 K
`d_(2)=?`
The density `(d_(2))` of the gas at STP can be calculated using the eqiation,
`d=(Mp)/(RT)`
`therefore (d_(1))/(d_(2))=((Mp_(1))/(RT_(1)))/((Mp_(2))/(RT_(2)))`
`rArrd_(1)/(d_(2))=(p_(1)T_(2))/(p_(2)T_(1))`
`=(1xx300xx5.46)/(2xx273)`
Hence, the density of the gas at STP will be 3 g `dm^(-3).`