Calculate the volume occupied by 8.8 g of `CO_(2)` at `31.1^(@)C` and 1 bar pressure. R= 0.083 bar L `K^(-1)mol^(-1).`

Answer

5.05 L

Explanation

It is known that,
`pV=m/MRT`
`rArr V=(mRT)/(Mp)`
Here,
m = 8.8 g
R= 0.083 bar `LK^(-1)mol^(-1)`
T = `31.1^(@)C` = 304.1 K
M =44 g
p = 1 bar
Thus, volume `(V)=(8.8xx0083xx304.1)/(44xx1)`
`" "=5.04806 L`
`" "5.05L`
Hence, the volume occupied is 5.05 L.