1g of graphite is burnt in a bomb calorimeter in excess of oxygen at 298 K and 1 atmospheric pressure according to the equation
C (graphite)`+O_(2)(g)rarrCO_(2)(g)`
During the reaction, temperature rises from 298 K to 299 K. If the heat capacity of the bomb calorimeter is 20.7kJ/K, what is the enthalpy change for the above reaction at 298 K and 1 atm?

Explanation

To determine the enthalpy change for the combustion of 1 gram of graphite in a bomb calorimeter, we can follow these steps:

### Step 1: Identify the given data
- Mass of graphite (C) = 1 g
- Temperature change (ΔT) = 299 K - 298 K = 1 K
- Heat capacity of the bomb calorimeter (C_v) = 20.7 kJ/K

### Step 2: Calculate the heat absorbed by the calorimeter
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