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DeltaU^(Θ) of combustion of methane is -...

`DeltaU^(Θ)` of combustion of methane is `-XkJ mol^(-1)`. The value of `DeltaH^(Θ)` is

A

`=DeltaU^(Ө)`

B

`gtDeltaU^(Ө)`

C

`ltDeltaU^(Ө)`

D

`=0`

Text Solution

Verified by Experts

Since `DeltaH^(theta)=DetlaU^(theta)+Deltan_(g)RT and DeltaU^(theta)=-XkJ "mol"^(-1)`
`DeltaH^(theta)=(-X)+Deltan_(g)RT.`
`rArrDeltaH^(theta)ltDetlaU^(theta)`
Therefore, alternative (iii) is correct.
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