Home
Class 12
CHEMISTRY
Non-stoichiometric cuprous oxide. Cu(2)O...

Non-stoichiometric cuprous oxide. `Cu_(2)O` can be prepared in laboratory. In this oxide, copper-to-oxygen ratio is slightly less than 2 : 1. can you account for the fact that this substance is a p-type semiconductors?

Text Solution

Verified by Experts

The ratio less than 2:1 in `Cu_(2)O` shows cuprous `(Cu^(+))` ions have been replaced by cupric `(Cu^(2+))` ions. For maintaining electrical neutrality, every two `Cu^(+)` ions will be replaced by one `Cu^(2+)` ion thereby creating a hole. As conduction will be due to the presence of these positive holes, hence it is a p-type semiconductor.
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    NCERT|Exercise Solved Examples|3 Videos
  • THE P-BLOCK ELEMENTS

    NCERT|Exercise EXERCISE|74 Videos

Similar Questions

Explore conceptually related problems

Select the correct statement, for non stoichiometric cuprous oxide Cu_(1.8)O .

Statement-1 : At a fixed temperature, silicon will have a minimum conductivity when it has a smaller acceptor doping. Statement-2 : The conductivity of an intrinsic semiconductor is slightly higher than that of a lightly doped p-type semiconductor.

The surface of copper gets tarnished by the formation of copper oxide. N_(2) gas was passed to prevent the oxide formation during heating of copper at 1250 K. However, the N_(2) gas contains 1 mole % of water vapour as impurity. The water vapour oxidises copper as per the reaction given below: 2Cu(s) + H_(2)O(g) rarr Cu_(2)O(s) + H_(2)(g) is the minimum partial pressure of H2 (in bar) needed to prevent the oxidation at 1250 K. The value of ln is ____. (Given: total pressure = 1 bar, R (universal gas constant) = 8 J K−1 mol^(−1), ln(10) = 2.3. Cu(s) and Cu_(2)O(s) are mutually immiscible. At 1250 K: 2Cu(s) + 1//2 O_(2)(g) rarr Cu_(2)O(s) triangle H^(theta) = − 78,000 J mol^(−1) H_(2)(g) + 1//2 O_(2)(g) rarr H_(2)O(g), triangle G^(theta) = − 1,78,000 J mol^(−1) , G is the Gibbs energy