Home
Class 12
CHEMISTRY
Gold (atomic radius = 0.144 nm) crystall...

Gold (atomic radius = 0.144 nm) crystallizes in a face centred unit cell. What is the length of a side of the cell?

Text Solution

Verified by Experts

Give r=0.144nm,a=?
For fcc, `a=2sqrt(2)r=2xx1.414xx0.144nm=0.407nm`
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    NCERT|Exercise Solved Examples|3 Videos

  • THE P-BLOCK ELEMENTS

    NCERT|Exercise EXERCISE|74 Videos

Similar Questions

Explore conceptually related problems

Gold (atomic radius = 0.154 nm ) crystallizes in a face centred unit cell. What is the length of a side of the cell.

Gold (atoic radius = 0.144 nm) crystallizes in a facelcentred unit cell. What is the length of a side of the cell?

Gold (atomic radius = 0.144nm) crystallises in a face centred unit cell. What is the length of the side of the cell ?

An element having an atomic radius of 0.14 nm crystallises in a fcc unit cell. What is the length of side of the cell ?