What is the area of the plates of a 2 farad parallel plate air capacitor, given that the separation between the plates is 0.5 cm?

Explanation

Capacitance of a parallel capacitors. V=2F
Distance between the two plates , d=0.5 cm =`0.5xx10^(-2) m `
capacitance of a parallel plate capacitor is given by the relation.
`C=(in_(0)A)/d`
`A=(Cd)/(in_(0))`
Where, `in_(0)`=Permitivity of free space =`8.85xx10^(-12) C^(2)N^(-1)m^(-2)`
` :. A=(2xx0.5xx10^(-2))/(8.85xx10^9-12)=1130 km^(2)`
Hence , the area of the plates is too large. to avoid this situtation , the capacitance is taken in the range of `muF`.