Is there any change in hybridisation of the `B` and `N` atom as a result of the following reaction?
`BF_(3)+NH_(3)rarr F_(3)B.NH_(3)`

Explanation

Boron atom in `BF_(3)` is `sp^(2)` hybridized. The orbital picture of boron in the excited state can be shown as :

Nitrogen atom in `NH_(3)` is `sp^(3)` hybridized. The orbital picture of nitrogen can be represented as :

After the reaction has occured , an adduct `F_(3)B.NH_(3)` is formed as hybridization of 'B' changes to `sp^(3)`. However, the hybridization of 'N' remain intact.