Home
Class 12
PHYSICS
An alternating current I=I(0) sin omega ...

An alternating current I=I_(0) sin omega t is flowing in a circuit.The ratio of rms current in the interval of 0 to T the average current in the circuit for the time interval from T/8 to 3T/8 (Where T is time period) is :

Promotional Banner

Similar Questions

Explore conceptually related problems

An alternating current I=I_(0)sinwt is flowing in a circuit. The ratio of rms current in the interval of 0 to T to the average current in the circuit for the time interval from T/8 to 3T/8 (Where T is time period) is :

Find the average value I_(m) of alternating current intensity over time interval from 0 to (pi)/(omega)

An alternating current is given by the equation i=i_(1)sin ω t+i_(2)cosω t .The rms current will be :

The average value of alternating current I=I_(0) sin omegat in time interval [0, pi/omega] is

An alternating current 'I' is given by I = i_(0) sin 2 pi (t//T + 1//4) . Then the average current in the first one quarter time period to

For an ac circuit V=15 sin omega t and I=20 cos omega t the average power consumed in this circuit is

If an alternating current is given by i = a sin ( omega t) + b cos ( omega t), then RMS value of current is :-

The average value of a.c. voltge E =E_(0) sin omega t over the time interval t = 0 to t = pi//omega is

In adjacent circuit, switch S is closed at t = 0. The time at which current in the circuit becomes half of the steady current is

What is the average value of atlernating current, I = I_(0) sin omega t over time interval t = pi//omega to t = pi//omega ?