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An alternating current I=I(0) sin omega ...

An alternating current I=I_(0) sin omega t is flowing in a circuit.The ratio of rms current in the interval of 0 to T the average current in the circuit for the time interval from T/8 to 3T/8 (Where T is time period) is :

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An alternating current I=I_(0)sinwt is flowing in a circuit. The ratio of rms current in the interval of 0 to T to the average current in the circuit for the time interval from T/8 to 3T/8 (Where T is time period) is :

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Knowledge Check

  • The average value of alternating current I=I_(0) sin omegat in time interval [0, pi/omega] is

    A
    `(2I_(0))/pi`
    B
    `2I_(0)`
    C
    `(4I_(0))/pi`
    D
    `I_(0)/pi`

  • An alternating current 'I' is given by I = i_(0) sin 2 pi (t//T + 1//4) . Then the average current in the first one quarter time period to

    A
    `(2i_(0))/(pi)`
    B
    `(i_(0))/(pi)`
    C
    `(i_(0))/(2 pi)`
    D
    `(3 i_(0))/(pi)`

  • For an ac circuit V=15 sin omega t and I=20 cos omega t the average power consumed in this circuit is

    A
    300 watt
    B
    150 watt
    C
    75 watt
    D
    zero

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