One mole of a diatomic gas is taken through the process P/T^(n)=K where n and K are constants.If the molar specific heat of the gas is C=-R/2 then the value of n is

One mole of a diatomic gas is taken through the process P/T^(n)=C,where n and C are constant.If the heat capacity of gas is C=-R/2, then value of n is

One mole of a diatomic gas undergoes a thermodynamic process, whose process equation is P prop V^(2) . The molar specific heat of the gas is

One mole of an ideal diatomic gas is taken through a process whose P-V diagram is shown in the figure. The work done by the gas is

One mole of an ideal monatomic gas undergoes the process P=alphaT^(1//2) , where alpha is constant . If molar heat capacity of the gas is betaR1 when R = gas constant then find the value of beta .

An ideal gas is made to undergo a process T = T_(0)e^(alpha V) where T_(0) and alpha are constants. Find the molar specific heat capacity of the gas in the process if its molar specific heat capacity at constant volume is C_(v) . Express your answer as a function of volume (V).

One mole of a monatomic gas is mixed with 3 moles of a diatomic gas. What is the molar specific heat of the mixture at constant volume?

One mole of an ideal monoatomic gas undergoes a process as shown in the figure. Find the molar specific heat of the gas in the process. R is a gas constant.

Two moles of a monatomic gas is mixed with three moles of a diatomic gas. The molar specific heat of the mixture at constant volume is