At 298K the conductivity of a saturated solution of AgCl in water is `2.6times10^(-6)Scm^(-1)` .Its solubility product at 298K
(given :
`lambda^(oo)` (`Ag^(+)`)=63.0 `Scm^(2)mol^(-1)`
`lambda^(oo)` `(Cl^(-))`=67.0 `Scm^(2)mol^(-1)` )

At 298 K, The specific conductivity of a saturated solution of silver chloride in water is 2.30xx10^(-5)Scm^(-1) . Calculate its solubility in gL^(-1) at 298 K. Given lambda_(m)^(@)(Ag^(+))" and "lambda_(m)^(@)(Cl^(-)) are 61.9 and 76.3 S cm^(2)mol^(-1) respectively.

The specific conductance of a saturated solution of AgCl in water is 1.826xx10^(-6)"ohm"^(-1)cm^(-1) at 25^(@)C . Calculate its solubility in water at 25^(@)C . [Given Lambda_(m)^(oo)(Ag^(+))=61.92" ohm"^(-1)cm^(2)mol^(-1) "and" Lambda_(m)^(oo)(Cl^(-))=76.34" ohm"^(-1)cm^(2)mol^(-1)] .

The conductivity of a saturated solution of AgCl at 25^(@)C after subtracting the conductivity of water is 2.28 xx 10^(-6) S cm^(-1) . Calculate the solubility product of AgCl at 25^(@)C if Lambda_(m)^(0) (AgCl) 138.3 S cm^(2) mol^(-1)

The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is:

The conductivity of 0.20 mol L^(-1) solution of KCI is 2.48xx10^(-2)S cm^(-1) . Calculate its molar conductivity and degree of dissociation (alpha) . Given lambda_((K^(+)))^(@)=73.5 S cm^(-2)mol^(-1)and lambda_((CI^(-)))^(@)=76.5 mol^(-1) lambda_((K^(+)))^(@)=73.5 S cm^(-2)mol^(-1)and lambda_((CI^(-)))^(@)=76.5 mol^(-1)