Fig. `4.134, ABC` is a right triangle right angled at `B and D` is the foot of the wedicular dnem from Ben `AC.` If `DM _|_ BC and DN _|_ AB,` prove that (i) `DM^2=DN xx MC` (ii) `DN^2=DM xx AN `

In Fig.4.121,ABC is a right triangle right angled at B and D is the foot ot the the perpendicular drawn from B on AC .If DM perp BC and DN perp AB ,prove that: (FIGURE) DM ^(2)=DN xx MC( ii) DN^(2)=DM xx AN

In Fig. 3, ABC is a right triangle, right angled at C and D is the mid-point of BC. Prove that AB^2 = 4AD^2 - 3AC^2 .

In Fig.3,ABC is a right triangle,right angled at C and D is the mid-point of BC.Prove that AB^(2)=4AD^(2)-3AC^(2)

In Fig.6.53,ABD is a triangle right angle at A and AC_|_BD .Show that (i) AB^2=BC.BD .

In Fig. D is point on hypotenuse AC of Delta ABC , BD bot AC DM bot BC and DN bot AB . Prove that : (i) DM^(2) = DN . MC , (ii) DN^(2) = DM . AN

Delta ABD is a right triangle,right-angled at A and AC perp BD. Prove that AB^(2)=BC xx BD

In a right angled triangle ABC,D is the foot of the perpendicular from B on the hypotenuse AC . If AB=3cm and BC=4cm, what is the area of /_\ABD

If ABC is a right triangle right-angled at B and M, N are the midpoints of AB and BC respectively. Then 4 (AN^2 + CM^2) =

In a right-angled triangle ABC , D is the foot of the perpendicular from B on the hypotenuse AC . If AB=3cm and BC=4cm, what is the area of /_\ABD?