What is the de-Broglie wavelength associated with an electron moving with an electron, accelerated through a potential difference of 100 volt?

Explanation

Accelerating potential V = 100 V. The de Broglie wavelength `lambda` is
`lambda=h//p=1.227/sqrtV nm`
`lambda=1.227/sqrt100 nm =0.123 nm `
The de Broglie wavelength associated with an electron in this case is of N8the order of X-ray wavelengths.