The radius of innermost electron orbit of a hydrogen atom is `5.3xx10^(-11)m`. What are the radii of n=2 and n=3 orbits.?

Explanation

The radius of the innermost orbit of a hydrogen atom `r_(1)=5.3xx10^(-11)m`
Let `r_(2)` be the radius of the orbit at `n=2` it is related to the radius of the innermost orbit as:
`r_(2)=(n)^(2)r_(1)`
`=4xx5.3xx10^(-11)=2.12xx10^(-10)m`
For n=3 we can write the corresponding electron radius as:
`r_(3)=(n)^(2)r_(1)`
`=9xx5.3xx10^(-11)=4.77xx10^(-10)m`
Hence, the radii of an electron for n=2 and n=3 orbits are `2.12xx10^(-10)m and 4.77xx10^(-10)` m respectively