Find the equation of a line which cuts off intercepts `a and b` respectively from the `x and y-a x e s` is `x/a+y/b=1`

Explanation

Given x-intercept =a⇒(a,0) is one point on the line


And y-intercept =b⇒(0,b) is another point on line


⇒equation of line =`y−0=(b−0​)/(0-a)(x−a)`


⇒`−ay=bx−ab`


...