The horizontal distance between two poles is 15 m. The angle of depression of the top of first pole as seen from the top of second pole is 30°. If the height of the second pole is 24 m, find the height of the first pole. Use v3 =1.732)

The horizontal distance between two poles is 15m. The angle of depression of the top of the first pole as seen from the top of the second pole is 30o .If the height of the second pole is 24m, find the height of the first pole.(sqrt(3)=1.732)

The horizontal distance between two towers is 60 metres. The angle of depression of the top of the first tower when seen from the top of the second tower is 30^(@) . If the height of the second tower is 90 metres. Find the height of the first tower. [Use sqrt(3)= 1.732 ]

The horizontal distance between two trees of different heights is 60m.The angle of depression of the top of the first tree when seen from the top of the second tree is 45o .If the height of the second tree is 80m, find the height of the first tree.

From the top of a 50m high tower,the angles of depression of the top and bottom of a pole are observed to be 45o and 60o respectively. Find the height of the pole.

A person observed that the angle of elevation at the top of a pole of height 5 metre is 30^(@) . Then the distance of the person from the pole is :

The angle of elevation of the top of a pole is 60^(@) . If the height of the pole increases, the angle of elevation will also increase.

From te top of a tower , 60 meters high, the angles of depression of the top and bottom of a pole are alpha and beta respectively .Find the height of the pole.