I+((2n)!)/(3!(2n-3)!)(dndn_(1))/(21(n-2!))" are in ratio "44:3" .Find "n

If ((2n)!)/(3!(2n-3)!) and (n!)/(2!(n-2)!) are in the ratio 44:3 find n.

If ((2n)!)/(3!(2n-3)!)a n d(n !)/(2!(n-2)!) are in the ratio 44 :3, find ndot

(i) If (n!)/(2.(n-2)!): (n!)/(4!.(n-4)!) = 2:1 , find the valye of n. (ii) If ((2n)!)/(3!(2n-3)!): (n!)/(2!(n-2)!) = 44:3 , then find the value of n.

(i) If (n!)/(2.(n-2)!): (n!)/(4!.(n-4)!) = 2:1 , find the valye of n. (ii) If ((2n)!)/(3!(2n-3)!): (n!)/(2!(n-2)!) = 44:3 , then find the value of n.

Solve for n : ((2n)!)/( 3!( 2n-3) !) : ( n!)/( 2!( n-2)!) = 44 : 3

If ((2n!))/((3!)xx(2n-3)!): (n!)/((2!)xx(n-2)!)=44:3 , find the value of n.

If ^(2n+1)P_(n-1):^(2n-1)P_(n)=3:5, find n

If ^(2n+1)P_(n-1):^(2n-1)P_(n)=3:5, then find the value of n.

If the ratio ^(2n)C_(3).^(n)C_(3) is equal to 11:1 find n

Find the sum of series upto n terms ((2n+1)/(2n-1))+3((2n+1)/(2n-1))^2+5((2n+1)/(2n-1))^3+...