[" A car battery has e.m.f."12" volt and internal resistance "5times10^(-2)" ohm.If it draws "60" amp current,the terminal voltage of "],[" the battery will be "]

A car battery has e.m.f. as 12V and internal resistance 5 xx 10^-2 Omega . If it draws 60 ampere current, the terminal voltage of battery will be

A car has a fresh storage battery of emf 12 V and internal resistance 5.0 xx 10^(-2) Omega . If the starter motor draws a current of 90A, what is the terminal voltage of the battery when the starter is on?

A car has a fresh storage battery of emt 12 V and internal resistance 5.0 xx 10^(-2) Omega . If the starter moter draws a current of 90A, what is the terminal voltage of the battery when the starter is on? (b) After long use, the internal resistance of the storange battery increase to 500 Omega . What maximum current can be drawn from the battery? Assume the emt of the battery to remain unchanged. (c) If the discharged battery is changed by an external emf source, is the terminal voltage of the battery during changing greater of less than is emf 12 V ?

A car has a fresh storage battery of e.m.f 12 V and internal resistance 2 xx 10 ^(-2) Omega . If the starter motor draws a current of 80 A. Then the terminal voltage when the starter is on is .

A storage battery has e.m.f. 15 volts and internal resistance 0.05 ohm . Its terminal voltage when it is delivering 10 ampere is

A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor. The current in the circuit is 0.5 A. The terminal voltage of the battery when the circuit is closed is

A battery of emf 10 V and internal resistance 3 ohm is connected to a resistor. The current in the circuit is 0.5 A. The terminal voltage of the battery when the circuit is closed is

A battery of emf 10 V and internal resistance 3Omega is connected to a resistor. The current in the circuit is 0.5A. The terminal voltage of the battery when the circuit is closed is

A battery having e.m.f. 5V and internal resistance 0.5 is connected with a resistance of 4.5 Omega , then the voltage at the terminals of the battery is