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int0^pi(sqrt(1+cos2x))/2dx...

`int_0^pi(sqrt(1+cos2x))/2dx`

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int_0^pi sqrt((1+cos2x)/2)dx= (A) 0 (B) 1 (C) 2 (D) none of these

Find the value of sqrt2int_0^(100pi)sqrt(1-cos2x)dx

int_0^(pi) (sqrt(1+cos2x)/(sqrt2)) dx =

int_0^(2pi) sqrt((1-cos2x)/2) dx =

The value of the integral sqrt2 int_0^pi sqrt(1-cos2x) dx is ?

Let I=int_0^(100pi)sqrt(1-cos2x)dx , then

int_(0)^(pi) sqrt((1+cos 2x)/(2))dx=

int_(0)^(2pi) sqrt(1-cos 2x)/(2)dx=