The sides `A Ba n dA C` of a triangle `A B C` are respectively `2x+3y=29a n dx+2y=16` respectively. If the mid-point of `B Ci s(5,6)` then find the equation of `B Cdot`

Explanation

Let co-ordinates of B be` (x_1,y_1) & C be (x_2,y_2)`

Here,`(5,6)` is the mid point,
so, ` (x_1+x_2)/2=5,(y_1+y_2)/2=6`

`⇒x_1+x_2=10,y_1+y_2=12`


Since, `B(x_1,y_1)` lies on the line
`2x+3y=29`

So,`2x_1+3y_1=29 ----(1)`


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