Show that the equations of the straight lines passing through the point `(3,-2)` and inclined at `60^@` to the line `sqrt(3)x+y=1 ` a r e `y+2=0` and `y-sqrt(3)x+(2+3sqrt(3))=0.`

Explanation

Given,`sqrt(3)x+y=1`

Thus the slope of line is `=(-a)/b

-sqrt(3)`

Let slope of line that passes through `(3,−2)` be m


`tan60=(m-(-sqrt(3)))/(1+m(-sqrt(3)))`

`=>sqrt(3)=(m-(-sqrt(3)))/(1+m(-sqrt(3)))`

when,`(m-(-sqrt(3)))/(1+m(-sqrt(3)))=+sqrt(3)`

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