A vertex of an equilateral triangle is `(2,3)` and the opposite side is `x+y=2.` Find the equations of other sides.

Explanation

Given line
`x+y−2=0 ->(1)`

with slope ` m_1=−1`

Let the slope of the line be m which makes an angle of `60^0` with line in `->1`

Then,

`tan(60)^0=(m_1-m)/(1+mm_1)`

`=>+-sqrt(3)=(m+1)/(m-1)`

`=>1+m=+-sqrt(3)(m−1)`

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