If the straight line `x/a+y/b=1` passes through the line point of intersection of the lines `x+y=3 `and `2x-3y=1` and is parallel to `x-y-6=0` , find `a` and `b`

Explanation

Given,

`x + y − 3 = 0 -> (1)`

`2x − 3y − 1 = 0->(2) `

Solving `(1)` and `(2)` using cross - multiplication method:
`x/(−1−9)=y/(−6+1)=1/(−3−2) `

`=> x = 2 , y = 1`

Given that the line `x/a+y/b=1`
pass through `(2, 1)`


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