Two consecutive sides of a parallelogram are `4x+5y=0a d n7x+2y=0.` If the equation of one diagonal is `11 x+7y=9,` Equation of other diagonal : (A) `11x + 7y =0` (B) `3x - 5y + 5 = 0` (C) `7x + 11y = 0` (D) `3x + 5y + 5 =0`

Explanation

We know that, diagonals of a Parallelogram bisect each other

`4x+5y=0`

`⇒y=(−4x)/5​`

From equation of diagonal

`11x+7y=9`

`11x+7(−4x​)/5=9`

`=>x=5/3​` and `y=(−4)/3​`

So, one vertices is `(5/3​,−4/3​)`

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