Find the equation of the straight line passing through the point of intersection of the lines `5x-6y-1=0a n d3x+2y+5=0` and perpendicular to the line `3x-5y+11=0.`

Explanation

To find the equation of the straight line passing through the point of intersection of the lines \(5x - 6y - 1 = 0\) and \(3x + 2y + 5 = 0\), and perpendicular to the line \(3x - 5y + 11 = 0\), we will follow these steps:

### Step 1: Find the point of intersection of the two lines.

We have the equations:
1. \(5x - 6y - 1 = 0\) (Equation 1)
2. \(3x + 2y + 5 = 0\) (Equation 2)

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