Three sides `A B ,A Ca n dC A` of triangle `A B C` are`5x-3y+2=0,x-3y-2=0a n dx+y-6=0` respectively. Find the equation of the altitude through the vertex `Adot`

Explanation

Given, `AB ,BC` and `CA`
are ` 5x-3y+2=0,x-3y-2=0` and `x+y-6=0`

Solving `AB` and `AC` we get value of `x` and `y` as `2` and `4`

Again, slope of BC is :--

`x-3y-2=0`

`x-2=3y`

`y=x/3-2/3`

Slope`=1/3`,

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