Show that the straight lines given by `x(a+2b)+y(a+3b)=a` for different values of `a` and `b` pass through a fixed point.

Explanation

The given equation can be put in the form

`=>x(a+2b)+y(a+3b)=a+b`

`=>ax+2bx+ay+3by=a+b`

`=>ax+ay-a+2bx+3by-b=0`

`=>a(x+y−1)+b(2x+3y−1)=0`
`
=>(x+y−1)+λ(2x+3y−1)=0`


Solving the above,
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