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If `a ,b ,c` are variables such that `3a+2b+4c=0` , then show that the family of lines givenby `a x+b y+c=0` pass through a fixed point. Also, find that point.

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Given,
`3a+2b+4c=0`
So, it can be written as,
`=>2b=-3a-4c`
`=>b=(−4c−3a)/2​`
Putting in `ax+by+c=0`we get,
`=>ax+((−4c−3a)/2​)y+c=0`
...
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