3*sin(ax+b)

Differentiate the functions with respect to x2 .cos(sin x)3sin(ax+b)4sec(tan(sqrt(x)))

If a, b ∈ [0,2pi] and the equation x^(2) + 4+3sin(ax+b)=2x has atleast one solution, and the least (+ve) . Value of a+b is k then,

If the equation x^(2)+4+3sin(ax+b)-2x=0 has at least one real solution, where a,b in [0,2pi] then one possible value of (a+b) can be equal to

If a,b in [0,2pi] and the equation x^(2)+4+3sin(ax+b)-2x=0 has at least one solution, then the value of (a+b) can be

If the equation x^(2)+4+3sin(ax+b)-2x=0 has at least one real solution, where a,b in [0,2pi] then one possible value of (a+b) can be equal to

If a,b in[0,2 pi] and the equation x^(2)+4+3sin(ax+b)-2x=0 has at least one solution,then the value of (a+b) can be (a) (7 pi)/(2) (b) (5 pi)/(2) (c) (9 pi)/(2) (d) none of these

sin (ax +b) cos (ax+b)

sin (ax +b) cos (ax+b)

Differentiate the functions with respect to x1.cos(sin x)2*sin(ax+b)3sec(tan(sqrt(x)))