Find the equation of the straight line passing through the point of intersection of `2x+3y+1=0 `an d `3x-5y-5=0` and equally inclined to the axes.

Explanation

To find the equation of the straight line that passes through the point of intersection of the lines \(2x + 3y + 1 = 0\) and \(3x - 5y - 5 = 0\), and is equally inclined to the axes, we will follow these steps:

### Step 1: Find the point of intersection of the two lines.
We have the equations:
1. \(2x + 3y + 1 = 0\) (Equation 1)
2. \(3x - 5y - 5 = 0\) (Equation 2)

From Equation 1, we can express \(y\) in terms of \(x\):
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