Find the equations of the lines through the point of intersection of the lines `x -y+1=0` and` 2x-3y+5= 0`whose distance from the point`(3, 2)` is `7/5`

Explanation

Given,

`x -y+1=0->(1)` and` 2x-3y+5= 0->(2)`


putting value of `x` from `(1)` in `(2)` we get,

`=>2(y-1)-3y+5=0`

`=>2y-2-3y+5=0`

`=>-y+3=0`

`=>y=3`

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