The heat of hydroggenation for 3-methylbutene and 2-pentene are 30-kcal/mol and -28kcal/ mol respectively . The heats of combustion of 2-methylbutane and pentane are -784 kcal/mol and -782 kcal /mol respectively. All the values are given under standard conditions. Taking into account that combustion of both akanes give the same products, what is `DeltaH` (in kcal.mol)n for the following reaction under same conditions ?

Options

A. 0
B. -4
C. -2
D. 2

Answer

B

Explanation

`DeltaH_(1)=-30kal//mol,DeltaH_(2)=(-784+782)kcal//mol, DeltaH_(3) =28 kcal//mol`
`rArrDeltaH_(1)+DeltaH_(2)+DeltaH_(3)=-4kcal//mol`