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Int the molecule CH(3)C-=C CH=CH(2) , th...

Int the molecule `CH_(3)C-=C CH=CH_(2)` , the maximum number of carbon atoms arranged lineearly is :

A

2

B

3

C

4

D

5

Text Solution

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The correct Answer is:
To determine the maximum number of carbon atoms arranged linearly in the molecule \( CH_3C \equiv CCH=CH_2 \), we can analyze the structure and hybridization of each carbon atom in the molecule. ### Step-by-Step Solution: 1. **Identify the Structure**: The molecule can be represented as follows: \[ CH_3 - C \equiv C - CH = CH_2 \] This shows a chain of carbon atoms with a triple bond and a double bond. 2. **Determine Hybridization**: - **Carbon 1 (C1)**: The first carbon (attached to three hydrogens) is \( sp^3 \) hybridized because it forms four sigma bonds (three with hydrogen and one with C2). - **Carbon 2 (C2)**: The second carbon (part of the triple bond) is \( sp \) hybridized because it forms one sigma bond with C1 and two pi bonds with C3. - **Carbon 3 (C3)**: The third carbon (also part of the triple bond) is \( sp \) hybridized, forming one sigma bond with C2 and one sigma bond with C4. - **Carbon 4 (C4)**: The fourth carbon (part of the double bond) is \( sp^2 \) hybridized because it forms one sigma bond with C3 and one sigma bond with C5, and has one pi bond with C5. - **Carbon 5 (C5)**: The fifth carbon (attached to two hydrogens) is \( sp^3 \) hybridized, forming three sigma bonds (two with hydrogen and one with C4). 3. **Analyze Linear Arrangement**: - The \( sp \) hybridized carbons (C2 and C3) are linear, meaning they can be arranged in a straight line. - The \( sp^2 \) hybridized carbon (C4) is trigonal planar, which also allows it to be in the same plane as C2 and C3. - The \( sp^3 \) hybridized carbons (C1 and C5) can also be arranged in the same plane due to their bonding. 4. **Count the Linear Carbons**: - The maximum number of carbon atoms that can be arranged linearly in this molecule is 4 (C1, C2, C3, and C4). C1 and C5 are not part of the linear arrangement because they are bonded to C2 and C4, respectively. ### Final Answer: The maximum number of carbon atoms arranged linearly in the molecule \( CH_3C \equiv CCH=CH_2 \) is **4**. ---

To determine the maximum number of carbon atoms arranged linearly in the molecule \( CH_3C \equiv CCH=CH_2 \), we can analyze the structure and hybridization of each carbon atom in the molecule. ### Step-by-Step Solution: 1. **Identify the Structure**: The molecule can be represented as follows: \[ CH_3 - C \equiv C - CH = CH_2 ...
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