Int the molecule `CH_(3)C-=C CH=CH_(2)` , the maximum number of carbon atoms arranged lineearly is :
A
2
B
3
C
4
D
5
Text Solution
AI Generated Solution
The correct Answer is:
To determine the maximum number of carbon atoms arranged linearly in the molecule \( CH_3C \equiv CCH=CH_2 \), we can analyze the structure and hybridization of each carbon atom in the molecule.
### Step-by-Step Solution:
1. **Identify the Structure**:
The molecule can be represented as follows:
\[
CH_3 - C \equiv C - CH = CH_2
\]
This shows a chain of carbon atoms with a triple bond and a double bond.
2. **Determine Hybridization**:
- **Carbon 1 (C1)**: The first carbon (attached to three hydrogens) is \( sp^3 \) hybridized because it forms four sigma bonds (three with hydrogen and one with C2).
- **Carbon 2 (C2)**: The second carbon (part of the triple bond) is \( sp \) hybridized because it forms one sigma bond with C1 and two pi bonds with C3.
- **Carbon 3 (C3)**: The third carbon (also part of the triple bond) is \( sp \) hybridized, forming one sigma bond with C2 and one sigma bond with C4.
- **Carbon 4 (C4)**: The fourth carbon (part of the double bond) is \( sp^2 \) hybridized because it forms one sigma bond with C3 and one sigma bond with C5, and has one pi bond with C5.
- **Carbon 5 (C5)**: The fifth carbon (attached to two hydrogens) is \( sp^3 \) hybridized, forming three sigma bonds (two with hydrogen and one with C4).
3. **Analyze Linear Arrangement**:
- The \( sp \) hybridized carbons (C2 and C3) are linear, meaning they can be arranged in a straight line.
- The \( sp^2 \) hybridized carbon (C4) is trigonal planar, which also allows it to be in the same plane as C2 and C3.
- The \( sp^3 \) hybridized carbons (C1 and C5) can also be arranged in the same plane due to their bonding.
4. **Count the Linear Carbons**:
- The maximum number of carbon atoms that can be arranged linearly in this molecule is 4 (C1, C2, C3, and C4). C1 and C5 are not part of the linear arrangement because they are bonded to C2 and C4, respectively.
### Final Answer:
The maximum number of carbon atoms arranged linearly in the molecule \( CH_3C \equiv CCH=CH_2 \) is **4**.
---
To determine the maximum number of carbon atoms arranged linearly in the molecule \( CH_3C \equiv CCH=CH_2 \), we can analyze the structure and hybridization of each carbon atom in the molecule.
### Step-by-Step Solution:
1. **Identify the Structure**:
The molecule can be represented as follows:
\[
CH_3 - C \equiv C - CH = CH_2
...
Topper's Solved these Questions
GENERAL ORGANIC CHEMISTRY
MS CHOUHAN|Exercise LEVEL- 1|1 Videos
FAMILIES OF CARBON COMPOUNDS: FUNCTIONAL GROUPS AND INTERMOLECULAR FORCES
MS CHOUHAN|Exercise ADDITIONAL OBJECTIVE QUESTIONS ( Matrix Match Type ) |4 Videos
GRIGNARD REAGENTS
MS CHOUHAN|Exercise Level 1 (Q.61 To Q.66)|1 Videos
Similar Questions
Explore conceptually related problems
The maximum number of carbon atoms arranged linearly in the molecule, CH_(3)-C-=C-CH=CH_(2) is
For a given molecule : CF_(2)=C=C=C=CH-CH_(3) ltbrrgt find the maximum number of atoms which may lie in the same plane.
In CO_(2),CH_(4) and CH_(3)^(+) the hybridisation of carbon atoms are
CH_(3)-CH=CH-CH_(2)C-=CH In the above compounds thehybridization of "1,3,5" carbon atoms is
CH_(3)-CH=CH-CH_(2)C-=CH In the above compounds the hybridization of "1,3,5" carbon atoms is
The maximum number of carbon atoms arranged in a straight line in the molecule, CH_(3)-CequivC-CH=CH-CH_(3)
Arrange the following alcohols in the order of increasing number of carbon atoms and get a family. Can we call this family a homologous series ? C_(2)H_(5)OH, CH_(3)OH, CH_(3)-CH_(2)-CH_(2)OH, CH_(3)-(CH_(2))_(3) -CH_(2)OH
{:(OH), (|),(CH_(2)-C-CH_(2)-COOH),(" "||),(" "CH),(" "|),(" "CH_(3)):} Total number of carbon atoms in parent carbon chain is :-