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Match the column I and II. (Matrix) {:...

Match the column I and II. (Matrix)
`{:(,"Column I",,"Column II"),((a),H_(3)C-CH=CH-CH_(3),(p),"Dipole" "(cis" gt "trans)"),((b), H_(3)C-CH=CH-CN,(q),"Dipole" "(trans" gt "cis)"),((c),H_(3)C-CH=CH-Cl,(r),"Melting point" "(trans" gt "cis)"),((d),Cl-CH=CH-Cl,(s),"Boiling point " "(cis" gt "trans)"):}`

Text Solution

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The correct Answer is:
a-p,r,s ; b-q,r ; c-q ,r ; d-p , r, s

As shown in fig. In the relation of dipole moment to configuraion is quite direct. If in a 1,2 -disubstitued alkene (XY=CYZ) X and Y are both electron donating or both electrons withdrawing , the dipole moment of the cis isomer will generally be sizeble whereas that of the trans isomer will be small or zero `(i.e.,mu_("cis")gtmu_("trans"))`. If on the other hand, X is electron donating and Y is electron withdrawing of vice versa, `mu_("trans")gtmu_("cis")`. In tribustituted alkenes XCH=CYZ the situation is less clear cut, though if Z is alkyl and X and Y are hologen or other strongly electron withdrawing groups, the disposition (cis or trans)

of X and Y will be decisive, Except for the case of cyclooctene, configuration can be inferred form dipole moment where known the differences are perhaps uncomfortably small. In the case of 1-chloro-2-iodoethylene the original,seemingly unresonable order of dipole moments was later reversed . In trans-cyclooctene, the normal `C_(2h)` symmetry of trans-XCH=CHY is reduced to at most `C_(2)`, threrefore the compound can have a dipole moment, whereas compound of `C_(2h)` symmetry cannot. That the moment is so large may be releated to the highly twisted nature of the dipole bond (torsion angle between `136^(@) and 157^(@))`
Dipole Moments and the Dopole `"Rule"^(a)`:
As for as the question is concerned, melting point of (trans `gt` cis) because trans from is more symmetrical than cis from .
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