How many meso isomers of `C_(4)H_(8)Cl_(2)` will be?

Options

A. 0
B. 1
C. 2
D. 3

Explanation

To determine how many meso isomers of \( C_4H_8Cl_2 \) exist, we need to follow these steps:

### Step 1: Identify the possible structures
The molecular formula \( C_4H_8Cl_2 \) suggests that there are multiple structural isomers possible. We can consider the following structural variations:
1. 1,1-Dichlorobutane
2. 1,2-Dichlorobutane
3. 1,3-Dichlorobutane
4. 1,4-Dichlorobutane
5. 2,2-Dichlorobutane
6. 2,3-Dichlorobutane
7. 1,1-Dichloro-2-methylpropane
8. 1,2-Dichloro-2-methylpropane
9. 1,3-Dichloro-2-methylpropane

### Step 2: Analyze each structure for stereocenters
A meso compound must have at least two stereocenters. Let's analyze the structures:

1. **1,1-Dichlorobutane**: No stereocenters (not a meso compound).
2. **1,2-Dichlorobutane**: One stereocenter (not a meso compound).
3. **1,3-Dichlorobutane**: One stereocenter (not a meso compound).
4. **1,4-Dichlorobutane**: No stereocenters (not a meso compound).
5. **2,2-Dichlorobutane**: No stereocenters (not a meso compound).
6. **2,3-Dichlorobutane**: Two stereocenters; check for symmetry.
- This compound has a plane of symmetry, thus it is a meso compound.
7. **1,1-Dichloro-2-methylpropane**: No stereocenters (not a meso compound).
8. **1,2-Dichloro-2-methylpropane**: No stereocenters (not a meso compound).
9. **1,3-Dichloro-2-methylpropane**: No stereocenters (not a meso compound).

### Step 3: Count the meso isomers
From the analysis, only **2,3-Dichlorobutane** qualifies as a meso compound. Therefore, there is **one meso isomer** of \( C_4H_8Cl_2 \).

### Final Answer
The number of meso isomers of \( C_4H_8Cl_2 \) is **1**.

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