Home
Class 12
CHEMISTRY
CH(2)=CH-CH=CH-CH=CH(2) How many geome...

`CH_(2)=CH-CH=CH-CH=CH_(2)`
How many geometrical isomers ar possible for this compound ?

A

2

B

3

C

4

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of geometrical isomers for the compound \( CH_2=CH-CH=CH-CH=CH_2 \), we will follow these steps: ### Step 1: Identify the Structure The compound is a linear chain of six carbon atoms with alternating double bonds. It can be represented as: \[ \text{C}_1 \text{C}_2 \text{C}_3 \text{C}_4 \text{C}_5 \text{C}_6 \] where \( C_2, C_4, \) and \( C_6 \) are involved in double bonds. ### Step 2: Identify SP2 Hybridized Carbons Geometrical isomerism occurs in compounds with at least two SP2 hybridized carbons. In this compound, the carbons involved in double bonds (C2, C4, and C6) are SP2 hybridized. ### Step 3: Check for Different Groups on SP2 Carbons For geometrical isomerism to occur, the SP2 hybridized carbons must have different groups attached. We analyze the double bond positions: - **C2**: Attached to \( H \) and \( CH_2=CH \) (different groups) - **C4**: Attached to \( H \) and \( CH \) (different groups) - **C6**: Attached to \( H \) and \( H \) (same groups) Since C6 has two identical hydrogen atoms, it does not contribute to geometrical isomerism. ### Step 4: Identify Possible Isomers The relevant double bonds for geometrical isomerism are at C2=C3 and C4=C5. Each of these double bonds can exhibit cis and trans configurations: - **C2=C3** can be cis or trans. - **C4=C5** can also be cis or trans. However, since C6 does not contribute to geometrical isomerism, we only consider the configurations of the two double bonds. ### Step 5: Count the Isomers The two double bonds can give rise to the following combinations: 1. **Cis-Cis** 2. **Cis-Trans** 3. **Trans-Cis** 4. **Trans-Trans** However, since C6 does not allow for geometrical isomerism, we can only have: - **Cis** and **Trans** configurations for the double bonds at C2=C3 and C4=C5. Thus, the total number of geometrical isomers is **2** (one cis and one trans). ### Final Answer The total number of geometrical isomers possible for the compound \( CH_2=CH-CH=CH-CH=CH_2 \) is **2**. ---

To determine the number of geometrical isomers for the compound \( CH_2=CH-CH=CH-CH=CH_2 \), we will follow these steps: ### Step 1: Identify the Structure The compound is a linear chain of six carbon atoms with alternating double bonds. It can be represented as: \[ \text{C}_1 \text{C}_2 \text{C}_3 \text{C}_4 \text{C}_5 \text{C}_6 \] where \( C_2, C_4, \) and \( C_6 \) are involved in double bonds. ...
Promotional Banner

Topper's Solved these Questions

  • ISOMERISM (STRUCTURAL & STEREOISOMERISM)

    MS CHOUHAN|Exercise Level 1 (Q.1 To Q.30)|13 Videos
  • ISOMERISM (STRUCTURAL & STEREOISOMERISM)

    MS CHOUHAN|Exercise Level 1 (Q.31 To Q.60)|9 Videos
  • GRIGNARD REAGENTS

    MS CHOUHAN|Exercise Level 1 (Q.61 To Q.66)|1 Videos
  • NOMENCLATURE AND CONFORMATIONS OF ALKANES AND CYCLOALKANES

    MS CHOUHAN|Exercise Additional Objective Questions (MCQ)|1 Videos

Similar Questions

Explore conceptually related problems

CH_(3)-CH=underset(Br)underset(|)C-underset(Cl)underset(|)C=CH-CH_(3) How many geometrical isomers are possible for this compound?

Me (CH=CH-CH=C=CH-CH=CH_(2) Total number of geometrical isomers possible for above compound are:

CH_(3)-Ch=CH-CH=CH-CH-CH_(3), total number of geometrical isomer is :

A compound (M) on ozonolysis produces following products. (X) O=CH-CH_(2)-CH=O (Y) CH_(2)=O (Z) CH_(3)-CH=O Analyse the products and answer the following questions : How many geometrical isomer are theoretically possible for this compound (M)?

No. of geometrical isomers possible for the compound CH_(3)-CH=CH-CH=CH-C_(2)H_(5)

CH_(3)-CH=underset(Br)underset(|)C-underset(Br)underset(|)C=CH-CH_(3) How many grometrical isomers of this compound are possible ?

CH_(3)CH=CH-CH=CH-CH_(2)CHOHCH_(3) How many isomers (geometrical and optical) are possible for the above - mentioned compound?