If `x=111........1(20 digits ) y=333........3(10 digits) z=222..........2(10 digits)` then `x-z` is

If x=111"...."(20 digits),y=333"...."(10digits) and z=222".....2"(10 digits), then (x-y^(2))/(z) equals.

If x = 111 ……….. 1 (20 digits), y = 333….3 (10 digits) and z = 222…. 2 (10 digits), then what is (x − y^2) / (z) equal to ?

If x = 1111..... 20 times, y = 333 ......... 10 times, z = 2222 ....... 10 times. Find the value of (x-y^(2))/(z)

Round off the following numbers as indicated : (ii) 25.653 ot 3 digits (ii) 4.996xx10^5 to 3 digits (iii) 0.6995 to 1 digit (iv) 3.350 to 2 digits. (v) 3.450 to 2 digits.

Round off the following numbers as indicated : (i) 15.654 upto 3 digits " " (ii) 15 . 75 upto 3 digits " " (iii) 15.654 upto 4 digits " " (iv) 15.65 upto 3 digits (v) 142667 upto 5 digits (vi) 5.996 xx 10^(5) upto 3 digits . (vii) 0.7995 upto 1 digit (viii) 2.5946 xx 10^(-4) upto 2 digits .

If n=10^(10)-1 the number of digits in n^(3) is

In a 2 digit number, the units place digit is x. If the sum of digits be 9, then the number is (10x – 9).

The sum of the digits of a two-digit number is 12. if 18 is subtracted from the number, then the digits interchange their places. Find the number. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Units digits is 5, tens digit is 7, and the number is 75. (B) Given that 120-9x-18=9x+12rArr90=18xrArrx=5 . (C) The number formed by interchanging the digits is 10x+(12-x)=9x+12 . (D) Let the digit in the units place be x. Then the digit in the tens place be (12-x). therefore The number is 10(12-x)+x=120-10x+x=120-9x .

The sum of the digits of a two-digit number is 11. if 9 is subtracted from the number, then the digits interchagne their places. Find the number. The following steps are involved in solving the above problem. Arrange them in sequential order (A) Let the units digit be x. therefore , the tens digit is (11-x). therefore The number is 10(11-x)+x=110-9x . (B) Given that 110-9x-9=9x+11rArrx=5 . (C) Units digit is S and tens digit is 6 and the required number is 65. (D) The number formed by interchanging the digits is 10x+(11-x)=9x+11 .